Solving Nonlinear Equations with Newton's Method

Rather than approximate the Jacobian, one could instead solve the equation for the Newton step approximately. An inexact Newton method [22] uses as a Newton step a vector s that satisfies the inexact Newton condition
The parameter ? (the forcing term) can be varied as the Newton iteration progresses. Choosing a small value of ? will make the iteration more like Newton's method, therefore leading to convergence in fewer iterations. However, a small value of ? may make computing a step that satisfies (1.10) very expensive. The local convergence theory [22, 42] for inexact Newton methods reflects the intuitive idea that a small value of ? leads to fewer iterations. Theorem 1.3 is a typical example of such a convergence result.
Let the standard assumptions hold. Then there are ? and ? such that, if x 0 ? ( ?), { ? n} ? [0, ?], then the inexact Newton iteration
where
converges q-linearly to x*. Moreover,
if ? n ? 0, the convergence is q-superlinear, and
if ? n ? K ? F ( x n) p for some K ? > 0, the convergence is q-superlinear with q-order 1 + p.
Errors in the function evaluation will, in general, lead to stagnation of the iteration.
One can use Theorem 1.3 to analyze the chord method or the secant method. In the...