TABLE OF CONTENTS Schedule 40 is quite adequate for the conditions of pressure and temperature specified. Pipe size to be found by trial. Assume 6 in std pipe size. D i = 0.5052 ft, A c= 0.2006 ft 2. For commercial steel pipe, surface roughness = 0.00015 ft ,
?/D i = 0.00015/0.5052 
0.0003
Specific gravity of liquid = 75/62.4 = 1.2, Viscosity = 0.28/1.2 = 0.233 cP
Vol. flow rate = 
= 1.783 ft 3/s, u = 1.783/0.2006 = 8.9 ft/s o.k.
Re. No. = 
= 1.35 10 5 f = 0.0033 from ff chart (Perry)*
Assume Dia = 4 in std = 0.3355 ft, A C = 0.088 ft 2, ?/D i = 0.00015/0.3355 
0.00045
u = 
= 20.17 ft/s which is too high. ? 4 in pipe is not suitable.
8 in id. pipe will give ? P < 1.04 si calculated for 6 in pipe.
6 in std. pipe Schedule 40 is to be recommended.
Answer is (B)
First calculate heats of reaction for each reaction from the given heats of formation using the relation
? H R = ?( ? H f) p - ?( ? H f) R Heats of reactions kcal/gmol @25 C, 1 atm
CH 3 CHO( g) + H 2( g) ? C 2 H 5 OH( g
