Introduction to Clustering Large and High-Dimensional Data

Chapter 11: Solutions to Selected Problems

Problem 2.1.6. True or False? If is the optimal partition, then x l ? c ( ) ? x l + 1.

Solution to Problem 2.1.6

Consider a four scalar set = {0, 1/9, 4/9, 1}. While the arithmetic mean of the set is 7/18 the optimal 2 cluster partition is , where and . In this case the mean fails to separate the optimal clusters.

Problem 2.2.2. Show that the k-means clustering algorithm does not necessarily lead to the optimal partition.

Solution to Problem 2.2.2

Consider the one dimensional data set = {0, 1, 1 + ?, 3}. Since the optimal partition should be convex (see Lemma 2.1.1 and Theorem 2.3.1) the three candidates for an optimal 2 cluster partition are

  1. ? (0) = {{0, 1, 1 + ?}, {3}} with .

  2. ? (1) = {{0, 1}, {1 + ?, 3}} with .

  3. ? (2) = {{0}, {1, 1 + ?, 3}} with .

Hence, when ? is a small positive number (for example 0 < ? < 0.05), one has


An application of a batch k-means iteration to ? (0) does not change the partition. The first variation of ? (0) is ? (0) itself. An application of k-means to ? (0) does not change the partition, and the algorithm misses the optimal partition ? (2).

Problem 2.2.3. Assume that the...

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