Appendix B: Standardized Normal Distribution's Area Tables

For z ? 3.0, entries are in abbreviated notation . - p, where

1 - F( z) = . 10 ^-p.

X is normally distributed with mean ? = 27 and standard deviation ? = 4. What is the probability X will exceed 41?

Answer: z = (41 - 27)/4 = 3.50,

P( X ? 41) =1 - F(3.50),

= 2.3263 10 ^-4 = 0.00023263.

From Example 1, what is the probability that X will be less than 41?

P( X < 41) = 1 - [1 - F(3.50)],

= 1 - 0.00023263,

= 0.99976737.

z	1 - F( z)	z	1 - F( z)	z	1 - F( z)	z	1 - F( z)
0.00	0.50000	0.40	0.34458	0.80	0.21186	1.20	0.11507
0.01	0.49601	0.41	0.34090	0.81	0.20897	1.21	0.11314
0.02	0.49202	0.42	0.33724	0.82	0.20611	1.22	0.11123
0.03	0.48803	0.43	0.33360	0.83	0.20327	1.23	0.10935
0.04	0.48405	0.44	0.32997	0.84	0.20045	1.24	0.10749
0.05	0.48006	0.45	0.32636	0.85	0.19766	1.25	0.10565
0.06	0.47608	0.46	0.32276	0.86	0.19489	1.26	0.10383
0.07	0.47210	0.47	0.31918	0.87	0.19215	1.27	0.10204
0.08	0.46812	0.48	0.31561	0.88	0.18943	1.28	0.10027
0.09	0.46414	0.49	0.31207	0.89	0.18673	1.29	0.098525
0.10	0.46017	0.50	0.30854	0.90	0.18406	1.30	0.096800
0.11	0.45620	0.51	0.30503	0.91	0.18141	1.31	0.095093
0.12	0.45224

< Previous Excerpt Next Excerpt >

Purchase This Book

Reliability Engineering Handbook, Volume 1