TABLE OF CONTENTS To determine the weight per foot of any piping insulation, use the pipe size and nominal insulation thickness to find the insulation weight factor F in the chart shown below. Then multiply F by the density of the insulation in pounds per cubic foot.
Example. For 4" pipe with 4" nominal thickness insulation, F = .77. If the insulation density is 12 pounds per cubic foot, then the insulation weight is .77 12 = 9.24 lb/ft.
| Nominal Pipe Size | Nominal Insulation Thickness | ||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|
| 1" | 1 " | 2" | 2 " | 3" | 3 " | 4" | 4 " | 5" | 5 " | 6" | |
| 1 | .057 | .10 | .16 | .23 | .31 | .40 | |||||
| 1 | .051 | .12 | .15 | .22 | .30 | .39 | |||||
| 1 | .066 | .11 | .21 | .29 | .38 | .48 | |||||
| 2 | .080 | .14 | .21 | .29 | .37 | .47 | .59 | ||||
| 2 | .091 | .19 | .27 | .36 | .46 | .58 | .70 | .83 | |||
| 3 | .10 | .17 | .25 | .34 | .44 | .56 | .68 | .81 | |||
| 3 | .15 | .23 | .31 | .41 | .54 | .66 | .78 | .. | .97 | ||
| 4 | .13 | .21 | .30 | .39 | .51 | .63 | .77 | .96 | 1.10 | ||
| 5 | .15 | .24 | .34 | .45 | .58 | .71 | .88 | 1.04 | 1.20 | ||
| 6 | .17 | .27 | .38 | .51 | .64 | .83 | .97 | 1.13 | 1.34 | ||
| 8 | .. | .34 | .47 | .66 | .80 | .97 | 1.17 | 1.36 | 1.56 | 1.75 | |
| 10 | .. | .43 | .59 | .75 | .93 | 1.12 | 1.32 | 1.54 | 1.76 | 1.99 | |
| 12 | .. | .50 | .68 | .88 |
