Dynamic Plasticity

In order to understand well the problem we have to show several concepts which are helping. We choose an octhaedrical plane and its normal (see Fig. 1.1.1). For a point of stress ( ? 1 , ? 2 , ? 3 ) we have the stress vector t n which must be projected on the hydrostatic line and on a normal to the hydrostatic line. Since
its components are
so that the projection of this vector on the hydrostatic line is
where ? is the mean stress. The projection on the hydrostatic line is now
with absolute value
The projection normal to the octhaedrical line is
with the absolute value
We got thus the interpretation of Ro and Eichinger [1926]: the absolute value of the vector tensor normal to the linear hydrostatic axes is equal to the square root of the second invariant of the deviatoric stress tensor. For notation we give
and
= ? ij ??? ij is the stress deviator.
Since the vector t ? in entirely in the octahedral plane, one can try to project it on various directions in this plane. Thus projecting on the ? plane is giving (see Fig. 1.1.2):
Now projecting on the
direction we have,
Thus we can write:
Taking into account that
we arrive at the relation
?
[0, ?/3] defines the orientation in...