Engineering Physics: Fundamentals and Modern Applications

Let S be a narrow slit illuminated by monochromatic light of wavelength ?, and S 1 and S 2 be the two narrow slits separated by a small distance 2 d (as in Figure 5). Let a screen XY be placed at a distance D from the coherent sources S 1 and S 2. Let O be the foot of the perpendicular drawn from C, the mid point of S 1 and S 2 on the screen. Now consider a point P on the screen at a distance x from O at which the condition for bright and dark fringes are to be determined. Draw S 1M and S 2N perpendiculars from S 1 and S 2 on the screen and join S 1P and S 2P. The path difference between the waves reaching at P from S 1 and S 2 is given by
In a right angled triangle S 2NP, we have
Using the binomial theorem and neglecting higher terms, since D >> x or d, we get
| (1) | |
Similarly in a right angled triangle S 1MP, we have
| (2) | |
? Path difference, 
| (3) | |
If the sources S 1 and S 2 are in the same phase as the waves reaching at P, the path differences must only be due to path difference, ?