EIT Industrial Review, Second Edition

In the 60-question afternoon session of the FE Exam, expect three questions on manufacturing processes, three questions on material handling, and three questions on manufacturing systems design.
For material removal by drilling, slab milling, and face milling, formulas for material removal rate ( MRR) are given on pages 109 of the Handbook.
Problem and Solution to Example
| 1. | A 3/8" bit is to drill four 6"-deep holes per minute in a hardwood slab. If it rotates at 1750 rpm, the required feed rate in inches per revolution is most nearly:
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Answers
| 1. | The required material removal rate is MRR = ( ?/4)(3/8) 2 4 6 in. 3/min. (not from the MRR formula given in the Handbook but directly from the volume of the cylinder of material that must be removed per minute). From the Handbook formula, MRR = ( ?/4)(3/8) 2 f 1750, where f is the feed rate in inches per revolution. Equating and solving for f, we have f= 24/1750 = 0.0137 inches per revolution. Response B is correct. |
Tolerances for dimensions are cited, e.g., 24.0 0.34 cm, which means, e.g., that work will be rejected if its dimension turns out to be less than 23.66 cm or more than 24.34 cm. If a process is working to an established tolerance, it is assumed that there is a 3-sigma risk, 0.0013 (from the normal table, page 10 of the Handbook)...