CHAPTER 7: SOLUTIONS
CHAPTER 7: SOLUTIONS
7.2.3.1 Application Example 7.7: Jacobian Matrices:
Q: | Given Find u 11, u 12, u 22, and l 21 In general, Forward and Backward Substitution. The solution of a simultaneous set of algebraic linear equations by triangular factorization involves two main steps:
Having found the table of factors as indicated previously, the following relations are used to complete the solution: Vector b is destroyed in this process and converted in situ to vector w. Since l 11 is unity, w 1 is simply b 1 as can be seen from the matrix solution Subsequent rows of w are found using As this equation is used, w 1 replaces b 1, w 2 replaces b 2, and so on. Having found w 1 a similar process is used to find x: By inspection, or Again, in situ technique is used and x n replaces w n. In row n ? 1: or Element x n ? 1 replaces w n ? 1. The process continues for rows n ? 2, n ? 3, , 1. In row r This completes the solution. |
Answers
Q: | Solution Given Find u 11, u 12, u 22 and l 21. In general: Since the first row... |