Problem A

A horizontal curve is shown in the Figure below. PI is located in the lake and inaccessible. Length of AB has been found to be 614.75 ft.

REQUIRED

1.	Determine the intersection angle at PI. 40 51 ? 22 37 ? 18 14 ? 4 23 ?
2.	Find the radius of the horizontal curve (ft). 2031.30 2030.30 2030.03 2033.31
3.	Determine the length of the horizontal curve (ft). 1445.74 1474.54 1447.54 1454.74
4.	Find the PT station. 75+89.75 79+58.74 79+60.54 79+67.74

Answers

1.	A I = 22 37 ? + 18 14 ? = 40 51 ?
2.	G T = R tan (I/2) T = (PC to A) + (A to PI) (PC to A) = (69+75) ? (65+13) = 462 ?
3.	C
4.	H PT= (65+13) + (14+47.54) = 79+60.54

Problem B

A highway right of way cuts across the west end of a property parcel. Half the width of the right of way is 50' as shown in the sketch below. The radius to the highway curve is 400' and the total central angle is 30 . The lot lines along the north and the south boundaries are parallel, are 100' apart. and lie on a line due East - West. The east property line lies on a bearing of N 30 E as shown. The intersection of the east right of way line and the south property line becomes the PC of a circular curve which will become the new western lot boundary.

REQUIRED