Filtering in the Time and Frequency Domains

L.I.
L.I.
L.I.
L.D.
L.I.
L.D.
L.I.
L.I.
u h( t) = c 1 e -4 t + c 2 e 4 t
u h( t) = c 1 e t + c 2 te t + c 3 t 2 e t
u h( t) = c 1 + c 2 t + c 3 t 2 + c 4 t 3
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u h( t) = c 1 e -3 t sin 4 t + c 2 e -3 t cos 4 t
| a ? b, | k( t - ?) = |
| a = b, | k( t - ?) = ( t - ?) e -b ( t - ? ) |
From (1.4-1), 
From (1.4-1), v 1( ?) =
v 2( ?) = 
From Problem 1-4, 

From (1.8-3), ![]()
From (1.6-3)
e -48
e ?
0
Figure A.1-7
k t( t - ?) =
e -( R/L )( t - ? ); h( t - ?) = u -1( t - ?) k 1( t - ?)
Figure A.1-8

General shape is shown in Fig. 1-5.
Response is that of (c) with T