Advanced Mechanics of Materials

Let us consider a simply supported beam of constant stiffness EI carrying a uniform load q = constant. (See [21] for a different way of solving this problem.) The differential equation for the deflection of this beam [21, p. 273]
is replaced by a difference equation (see Chapter 6),
where q i = q 0 = constant. Because of the symmetry of the problem we put the origin of the coordinate system at the midspan (Fig. 8-86a) and consider only the portion of the beam shown in Fig. 8-86b. The symmetry implies that
In addition to the boundary conditions (8-306) we also have the boundary conditions at x = l/2,
Conditions (8-306) when applied at 0 as the pivotal point result in
Therefore,
Boundary conditions (8-307) imply that at the pivotal point x n = l/2 we have
Together we have n + 5 equations: n + 2 Eq. (8-305), four Eqs. (8-308), and Eqs. (8-309). The number of unknowns also equals n + 5. The smallest index of the unknown in Eq. (8-305) is ?2 for i = 0 whereas the largest occurs for i = n and equals n + 2. Ultimately our equations become

where
The solution to this system gives the deflection Y i at all points of division. Specifically, we find that
We now easily...