TABLE OF CONTENTS The open-loop controller shown in Figure 3.1 consists of an integrated circuit differential amplifier. Determine the open-loop gain.
Solution:
Let V out = V a + V b
V a / V 1 = R f / R in
V b / V 2 = [R f / (R f + R in)] [(R f + R in) / R in] = R f / R in
V out / V 1 / (R f / R in) + V 2 / (R f / R in)
V out = (R f / R in) (V 2 V 1) = 100 Asin( ?t + ? ??t) = 100 Asin ?
The closed-loop controller shown in Figure 3.2 consists of an integrated circuit differential amplifier, and two cascaded inverting op amps. Determine the closed-loop gain.
Solution:
A v = R 2 / R 1 = 100
A f = (-R 1 / R 2)(-R 1 / R 1) = R 1/ R 2 = 0.01
V out = (V in V f) A v
V f = V out A f
V out = (V
