350 Solved Electrical Engineering Problems: For the FE/PE Exams in Electrical Engineering

The common gate FET circuit shown in Figure 2.11 has the following parameters. Forward transadmittance, y fs, equals 1.5 10 ?3 siemens. Output conductance, y os, equals 10 10 ?6 siemens. Gate-to-source resistance, r gs, equals 1 10 8 ohms. Gate-to-drain resistance, r gd, equals 1 10 8 ohms. Calculate the (a) Z in, (b) Z out, and (c) A v respectively.
Solution:
r d = 1/y os = 1 10 5 ohms
g m = y fs = 1.5 10 ?3
? = y fsr d = g mr d = 1.5 ?3 1 10 5 = 150
Z in = (r d + R D)/( ? + 1) R s
Z in = (1.1 10 5/151) (1.5 10 3) = 728 (1.5 10 3) = 490 ohms
Z out = [r d ( ? + 1)R s] R D = [1 10 5 + (151)1.5 10 3] (1 10 4)
Z out = (3.265 10 5) (1 10 4) = 9,969 ohms
A v = ( ?