350 Solved Electrical Engineering Problems: For the FE/PE Exams in Electrical Engineering

2.10: Common source amplifier

2.10 Common source amplifier

The common source FET circuit shown in Figure 2.10 has the following parameters. Forward transadmittance, y fs, equals 1.5 10 ?3 siemens. Output conductance, y os, equals 10 10 ?6 siemens. Gate-to-source resistance, r gs, equals 1 10 8 ohms. Gate-to-drain resistance, r gd, equals 1 10 8 ohms. Calculate the (a) Z in, (b) Z out, and (c) A v respectively.


Figure 2.10: Common source amplifier

Solution:

r d = 1/y os = 1 10 5 ohms

g m = y fs = 1.5 10 ?3

? = y fsr d = g mr d = 1.5 10 ?3 1 10 5 = 150

  1. Z in = R G r gs = (1 10 6) (1 10 8) = 9.9 10 5 ohms

  2. Z out = R D rd = R D 1/y os = (1 10 4) (1 10 5) = 9,090 ohms

  3. A v = ??[R D /(r d + R D)] = ?(g mr d)[R D/(r d + R D)]

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