350 Solved Electrical Engineering Problems: For the FE/PE Exams in Electrical Engineering

2.8: Common base amplifier

2.8 Common base amplifier

The common base BJT circuit shown in Figure 2.8 has the following hybrid parameters. Input impedance, h ie, equals 2 10 3 ohms. Voltage feedback ratio, h re, equals 4 10 ?4. Current gain, h fe, equals 50. Output admittance, h oe, equals 20 10 ?6 siemens. Calculate the (a) Z in, (b) Z out, (c) ?, and (d) A v respectively.


Figure 2.8: Common base amplifier

Solution:

Since h oeR C ? 0.1

  1. Z in = h ie / (1 + h fe) R E = (2 10 3/51) = 36 ohms

  2. Z out = (1 + h fe)/h oe R C = (51 / 20 10 ?6) (5.1 10 3) = 5.1 10 3 ohms

  3. ? = h fe /(1 + h fe) = 50/51 = 0.98

  4. A v = (h feR C)/h ie = (50 5.1 10 3)/(2 10 3) = 127

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