Programmed Review for Electrical Engineering, Third Edition

The problem in this section illustrates the application of three fundamental engineering parameters.
Q:
A hoist driven by a three-phase electric motor has a 4000-pound load capacity.
How much energy in joules and power in KW is required to raise a full capacity load 100 feet in one minute?
What motor capacity in HP is required to drive the hoist if the hoisting machinery is only 75% efficient?
Answers
Q:
1 watt-second = 1 joule = 0.738 lb-ft
(answer)
(answer)
= 9033 W or 9.033 KW
(answer)
If your answers are correct, go on to Problem 2-3.
If your answers are not correct, review p. 3.