Introduction to Optics

Annex 5.C: Interference Using Polarized Light Beams. Wave Plates

5.C.1 Orthogonally Polarized Beams Are Unable to Interfere

Let us first consider two scalar signals, ( S 1, S 2), with sinusoidal time variations of the same frequency ?, let ( A 1, A 2) and ( I 1, I 2), respectively, be their amplitudes and intensities. The two signals are considered to interfere if the response of a detector, receiving them simultaneously, is not equal to the addition of the responses obtained for separate receptions, but depends on their phase difference. More accurately, we can write


The superposition of the two signals is written as


The corresponding intensity is


The last term of (5.C.1) describes the interference phenomenon.

Instead of scalar signals let us now consider vector signals V 1 and V 2


The intensity corresponding to the superposition of the two signals V 1 and V 2 is given by


If the two vectors A 1 and A 2 are parallel, formulas (5.C.1) and (5.C.2) are identical, but if they are orthogonal, their scalar product is equal to zero and the interference term disappears: I = I 1 + I 2. Two orthogonal vector signals cannot interfere.

A Polarizer Allows the Interference of Two Orthogonal Vector Vibrations

Two polarized light beams, having any initial polarization, after having been transmitted by a polarizer, are parallel to the direction of the polarizer and are thus able to interfere. In Figure 5.C.1 have been...

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