Numerical Analysis Using MATLAB and Spreadsheets

Let the solutions of the homogeneous ODE
be of the form
Then, by substitution of (5.20) into (5.19) we get
or
We observe that (5.21) can be satisfied when
but the only meaningful solution is the quantity enclosed in parentheses since the latter two yield trivial (meaningless) solutions. We, therefore, accept the expression inside the parentheses as the only meaningful solution and this is referred to as the characteristic (auxiliary) equation, that is,
Since the characteristic equation is an algebraic equation of an nth-power polynomial, its solutions are s 1, s 2, s 3,..., s n and thus the solutions of the homogeneous ODE are:
If the roots of the characteristic equation are distinct (different from each another), the n solutions of (5.23) are independent and the most general solution is:
If two or more roots of the characteristic equation are repeated (same roots), then some of the terms of (5.24) are not independent and therefore (5.25) does not represent the most general solution. If, for example, s 1 = s 2, then,
and we see that one term of (5.25) is lost. In this case, we express one of the terms of (5.25), say k 2e s 1t as k 2te s 1t. These two represent two independent solutions and therefore the most general solution...