Electrodynamics: An Introduction Including Quantum Effects

We first demonstrate that TM and TE waves are not transversal, i.e. they do possess longitudinal components. In the cases of TE and TM waves the expressions for E ? and B ? in Eqs. (14.20) and (14.21) also simplify. Setting
we obtain from Eqs. (14.20) and (14.21) for ? 2 ? 0:
TM: B z = 0 everywhere,
TE: E z = 0 everywhere,
TM: Inserting in the second of Eqs. (14.67) the expression for ? ? E z from the first of Eqs. (14.67), we obtain
TE: Inserting similarly in Eqs. (14.68) the expression of the equation for ? ? B z into the other, we obtain
We conclude: E z, B z ? 0, because from Eqs. (14.67) for TM
and from Eqs. (14.68) for TE
Thus the components E z (TM), B z (TE) are not both zero; i.e. the TM and TE waves are not transversal waves, they possess longitudinal components E z and B z.
We saw previously (see Eqs. (14.30)), that E( x, y), B( x, y) satisfy the equations
(i.e. for each of the three components of E and B). We have therefore in particular for the z-components
TM:
TE:
Equations (14.72) and (14.73) together with their boundary conditions define an eigenvalue problem for the determination...