Electrodynamics: An Introduction Including Quantum Effects

14.6: TM and TE Waves in Wave Guides

14.6 TM and TE Waves in Wave Guides

14.6.1 General Considerations

We first demonstrate that TM and TE waves are not transversal, i.e. they do possess longitudinal components. In the cases of TE and TM waves the expressions for E ? and B ? in Eqs. (14.20) and (14.21) also simplify. Setting


we obtain from Eqs. (14.20) and (14.21) for ? 2 ? 0:

TM: B z = 0 everywhere,


TE: E z = 0 everywhere,


TM: Inserting in the second of Eqs. (14.67) the expression for ? ? E z from the first of Eqs. (14.67), we obtain


TE: Inserting similarly in Eqs. (14.68) the expression of the equation for ? ? B z into the other, we obtain


We conclude: E z, B z ? 0, because from Eqs. (14.67) for TM


and from Eqs. (14.68) for TE


Thus the components E z (TM), B z (TE) are not both zero; i.e. the TM and TE waves are not transversal waves, they possess longitudinal components E z and B z.

We saw previously (see Eqs. (14.30)), that E( x, y), B( x, y) satisfy the equations


(i.e. for each of the three components of E and B). We have therefore in particular for the z-components

TM:


TE:


Equations (14.72) and (14.73) together with their boundary conditions define an eigenvalue problem for the determination...

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